1792 United States presidential election in New York

1792 United States presidential election in New York
November 20, 1792 1796 →
President before election; George Washington; Independent	Elected President ; George Washington; Independent

A presidential election was held in New York on November 20, 1792, as part of the 1792 United States presidential election.^[1] The New York State Legislature chose 12 members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast 2 votes for president.

New York's 12 electors each cast one vote for incumbent George Washington and one vote for George Clinton in the state's first presidential election.^[2] (Although the state had ratified the Constitution to become the eleventh state on July 26, 1788, it did not participate in the first presidential election in 1789 due to the state legislature's being deadlocked.)

References

^ Hutchins, Stephen C., ed. (1879). Civil List and Forms of Government of the Colony and State of New York. Albany. p. 344.
^ 1792 Presidential Electoral Vote Count Dave Leip's Atlas of U.S. Presidential Elections.

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[1] Hutchins, Stephen C., ed. (1879). Civil List and Forms of Government of the Colony and State of New York. Albany. p. 344.

[2] 1792 Presidential Electoral Vote Count Dave Leip's Atlas of U.S. Presidential Elections.

[1]

v t e State results of the 1792 U.S. presidential election
Candidates	George Washington
General articles	Election timeline
Local results	Connecticut Delaware Georgia Kentucky Maryland Massachusetts New Hampshire New Jersey New York North Carolina Pennsylvania Rhode Island South Carolina Vermont Virginia
Other 1792 elections	House Senate

See also

References