1792 United States presidential election in Kentucky

A presidential election was held in Kentucky between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President. It was the first presidential election Kentucky participated in since being admitted to the Union on June 1, 1792.^[1]

Kentucky cast four electoral votes for the Independent candidate and incumbent President George Washington, as he ran effectively unopposed. The electoral votes for Vice president were cast for Democratic-Republican Thomas Jefferson from Virginia, the only state to do so. The state was divided into four electoral districts with one elector each, whereupon each district's voters chose the electors.^[2]

Results

1792 United States presidential election in Kentucky^[3]^[4]
Party		Candidate	Electoral vote	%
	Independent	George Washington	4	100.00%
Total votes			4	100.00%

^ Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson: McFarland & Company. ISBN 9780786410170.
^ "1792 Presidential General Election Results". U.S. Election Atlas. Retrieved 2023-07-14.
^ ^a ^b "A New Nation Votes". elections.lib.tufts.edu. Retrieved 2026-04-12.
^ "1792 Presidential Election". 270towin.com. Retrieved 2023-07-14.

v t e State results of the 1792 U.S. presidential election
Candidates	George Washington
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Other 1792 elections	House Senate